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Sum of three consecutive no of 4 no.A,B,C,D are 4613 ,4961,5010,5099.
what is the largest no among ABCD ??
JUSTIFIED the ans
Read Solution (Total 4)
-
- A+B+C=4613...........1
B+C+D=4961...........2
C+D+A=5010...........3
D+A+C=5099...........4
ADD ALL 1,2,3,4
YOU WILL GET
3(A+B+C+D)=4613+4961+5010+5099
NOW SUBSTITUTE VALUE FROM 1,2,3,4 YOU WILL GET THE ANSWER I THINK ITS D - 12 years agoHelpfull: Yes(23) No(3)
- A+B+C=4613
A+C+D=4961
A+B+D=5010
A+B+D=5099
adding all:
3(A+B+C+D)=19683
A+B+C+D=6561
Substract each sum and You will get the ans.
therfore, D is largest no. - 12 years agoHelpfull: Yes(14) No(2)
- 1948 is answer
- 12 years agoHelpfull: Yes(9) No(1)
- surely it is D
- 12 years agoHelpfull: Yes(5) No(2)
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