The perimeter of a equilateral triangle and regular hexagon are equal.Find out the ratio of their areas?
1)3:2
2)2:3
3)1:6
4)6:1

• Given that perimeter of equ.triang and hexagon are equal.consider length of triang
  as 'x' and length of hex as 'y'.so the relation is x=2y.Hexagon is made of six equ traingles and formula for area of equ triang is sqrt(3)/4*x^2 and using this we get ratio of areas as 2:3
• 11 years agoHelpfull: Yes(49) No(9)
• 6r=3a a/r=2
  now are
  (sqrt(3)/4)a^2:3sqrt(3)/2 r^2
  ->a^2/r^2:3*2 =4:6=2:3
• 11 years agoHelpfull: Yes(21) No(2)
• gyus this question came in my paper today .i feel that allmost 28 questions from m4maths
• 8 years agoHelpfull: Yes(4) No(1)
• ans is 2:3
  
• 11 years agoHelpfull: Yes(3) No(3)
• answer is 3:2
  perimeter of triangle: 3a
  perimeter of hexagon:6a
  consider side of tringle as 10 and side hexagon as 5.
  so d perimeters are equal 3*10=30= 6*5
  area of triangle sqt(3)/4 * a^2.
  area of hexagon 3 sqt(3)/4 * a^2.
  by canclng common terms on both sides. v get d answr #:2
• 9 years agoHelpfull: Yes(3) No(10)
• ans is 3/2
• 11 years agoHelpfull: Yes(1) No(7)
• perimeter of a equi triangle = perimeter of hexagon
  i.e. 3a=6a
  hence a=2
  so if you solve this you wil get 1:6
  
• 9 years agoHelpfull: Yes(1) No(10)
• hi manish..pls mail me some questions at ashwani.viswanathan@gmail.com
  
• 11 years agoHelpfull: Yes(0) No(9)
• ans is 3:2
• 11 years agoHelpfull: Yes(0) No(11)
• From given statement 3a=6b where a is side of equilateral triangle and b is side of hexagon. Area of equilateral triangle is (sqrt(3)/4)*a^2. area of hexagon is 6 times that of area of triangles with side b. So the area of hexagon is (3/2)*sqrt(3)*b^2. By substituting b in terms of a and taking the ratio of areas of both triangle and hexagon we obtain the result as 2:3
• 6 years agoHelpfull: Yes(0) No(0)
• perimeter of equilateral triangle=3*side of triange(s1)
  perimeter of hexagon=6*side of hexagon(s2)
  area of equilateral triangle A1=(sqrt(3)/4)*s1*s1 =>s1*s1=(4*A1)/sqrt(3)
  area of hexagon A2=(3*sqrt(3)/2)*s2*s2 =>s2*s2= (2*A2)/(3*sqrt(3))
  GIVEN:
  3*s1=6*s2
  squaring it we get
  9*s1*s1=36*s2*s2;
  substituting the values calculated through area in above equation
  9*4*A1/sqrt(3) =36*2*A2/(3*sqrt(3))
  ==>A1/A2=2/3
  2:3
• 6 years agoHelpfull: Yes(0) No(0)
• option 2 ...
• 5 years agoHelpfull: Yes(0) No(0)
• 1:6 area of equilateral triangle:area of hexagon
• 5 years agoHelpfull: Yes(0) No(0)
• 2:3 is the answer
• 5 years agoHelpfull: Yes(0) No(0)
• side of triangle let be 't'
  side of hexagon='h'
  according to qstn, 6h=3t
  =>t=2h
  ratio of areas
  sq root(3)/4 t^2/6*sq root(3)/4h^2
  putting t=2h;
  ratio = 2/3
• 3 years agoHelpfull: Yes(0) No(0)