In a triangle ABC, the lengths of the sides AB and AC equal 17.5 cm and 9 cm respectively. Let D be a point on the line segment BC such that AD is perpendicular to BC. If AD = 3 cm, then what is the
radius (in cm) of the circle circumscribing the triangle ABC?
A. 17.05 B. 27.85 C. 22.45 D. 32.25 E. 26.25

• circum radius = R
  Area of the triangle ABC = Δ = ½ (BC)(AD) = ½ (a)(3) = 3a/2
  The formula here is : R = abc/4Δ = abc / 4(3a/2) = bc/6 = (17.5)(9)/6 = 26.25
• 10 years agoHelpfull: Yes(29) No(2)
• draw the diagrm:
  AC=9,AB=17.5,AD=3
  THEN from property CD=8.48
  FROM A THEORM OF X STANDARD
  (AD)^2=CD*DB
  THUS DB=1.06
  NOW R=abc/4*area
  area=14.31
  abc=1502.55
  thus R=26.25
  
  
  
  
• 12 years agoHelpfull: Yes(21) No(12)
• @goldyy how DB= 1.06,IF U USE PYTHAGORAS,BD COMES OUT TO BE 17.24,AS AB^2-AD^2=BD^2= 17.24
• 12 years agoHelpfull: Yes(11) No(3)
• Area of a triangle = , where a, b and c are lengths of the sides of the triangle and R is the radius of the circle circumscribing the triangle
  
  In this example, area of the triangle =
  
  The area of any triangle can also be expressed as , as the altitude AD to the side BC is 3 cms.
  
  Equating the two and solving for R, we get R = 26.25 cms
  
• 12 years agoHelpfull: Yes(7) No(3)
• @ goldy from where abc comes ?
• 12 years agoHelpfull: Yes(1) No(3)
• Ans=26.25
  Draw atriangle a,b,c points
  BC=a, AC=b, AB=c;
  AB=c=17.5; AC=b=9; BC=a;
  Height=AD=3; to find circum of triangle=R
  area of triangleABC=1/2(BC)(AD)=1/2(a)(3)=3a/2
  R=abc/4xarea of triangle
  R=abc/4(3a/2)=bc/6=(17.5)(9)/6=26.25
• 7 years agoHelpfull: Yes(1) No(0)