TCS
Company
a hollow cube of 5cm is taken with a thickness of 1cm,it is made of smaller cubes of size 1cm if 4 faces of the outer side of the cube are painted totally how many faces of the smaller cube remain unpainted?
Read Solution (Total 4)
-
- Correction:
Faces of smaller cube painted = 4*5*5 = 100
Total no. of small cubes = 5*5*5-3*3*3 = 98
Total faces of small cubes = 6*98 = 588
Unpainted faces of smaller cube = 588-100 = 488 - 12 years agoHelpfull: Yes(30) No(5)
- Faces painted = 6*5*5 = 150
Total no. of small cubes = 5*5*5-3*3*3 = 98
Total faces of small cubes = 6*98 = 588
Unpainted faces of smaller cube = 588-150 = 438 - 12 years agoHelpfull: Yes(4) No(13)
- Ans is 18cubes
since it is HOLLOW CUBE so toally one face consists of 25 cubes and 4faces are painted remaining 2faces are unpainted so each face 9 unpainted so 9*2(unpainted) 18faces
AND MAX CUBES IN 5by5 is 125 how can answer be 4hunders change - 12 years agoHelpfull: Yes(4) No(2)
- ANS 50
total no of small cubes at faces=25*6=150
no of smal cubes painted=25*4=100
unpainted=150-100=50 - 12 years agoHelpfull: Yes(1) No(4)
TCS Other Question