the radius of the circle is reduced from 5cm to 4cm then the % change of area .

• for 5cm -> pi*r^2 --> 3.14 * 5 ^ 2 -> 78.539
  for 4cm -> pi*r^2 --> 3.14 * 4 ^ 2 -> 50.265
  
  %change -> (1- 50.265/78.539)*100= 36
  ie 36%
• 11 years agoHelpfull: Yes(11) No(2)
• percentage change in area =pi(5^2)-p1(4^2)/(pi(5^2))=0.36
  36%
• 11 years agoHelpfull: Yes(10) No(1)
• The change in the area is 36%
  
  
• 11 years agoHelpfull: Yes(2) No(1)
• Change in radius=20%.Thus new radius is 0.8R(R is the old radius).Hence,new area =pi*(0.8R)^2=pi*0.64R.Thus the change in area is 1-0.64=0.36=36%.
• 9 years agoHelpfull: Yes(0) No(0)
• Radius is reduced to 4 from 5 which is 20%. 20+20-(20*20/100) = 36
  So 36% decrease in area
• 8 years agoHelpfull: Yes(0) No(0)
• (pi*(5^2-4^2)/pi*5^2)*100
  ((25-16)/25)*100
  4*9=36%
• 7 years agoHelpfull: Yes(0) No(0)