If we consider all possibilities of words from the letters of MONOS, then what is the probability that O’s never come together

• MNSOO can be arranged in 4! ways =24 ways
  Total no. of arranging MONOS=5!/2=60
  so, probab= (60-24)/60=36//60=3/5
• 12 years agoHelpfull: Yes(35) No(5)
• Monos:-
  O---O:6 ways
  o--o-: 6 ways
  o-o--: 6 ways
  same thing from left to right
  18*2=36
• 12 years agoHelpfull: Yes(11) No(1)
• ans 4/5
  mnsoo arranged in 4!/2!=16
  Total no. of arranging MONOS=5!/2=60
  so, probab= (60-16)/60=48//60=4/5
• 12 years agoHelpfull: Yes(1) No(8)
• PLEASE TELL ME WEATHER I AM WRONG OR RIGHT
  MONOS ,TOTAL WORDS=5!/2!=60
  WHEN S AND O ARE TOGETHER, WE HAVE MON+SO/OS=4!*2!=48
  WHEN S AND O ARE NEVER TOGETHER,WE HAVE 60-48=12
  SO P()=12/60=1/5
  TELL ME WHERE I AM WRONG
• 12 years agoHelpfull: Yes(0) No(2)