From a circle of radius 10 cm a sector of 40% area is removed. a cone is formed with the remaining part of the circle. find the ratio of the radius and height of the cone?
> 1/2
>2/3
>3/4
>4/3

• 3/4 is the ans
  
• 12 years agoHelpfull: Yes(11) No(10)
• 40% of Pi*(10)^2=40*pi...now 40pi is the curved surface area of the cone..so remaining 60pi=pi*r*10..which gives r=6...and also 10^2=h^2+ r^2..putting the value of r here we get h=8...threfore r:h=6/8=3/4
• 11 years agoHelpfull: Yes(4) No(0)
• major sector length= 160pi/9.
  it is = to base of cone i.e bottom circle.
  =>2 pi r= 160pi/9
  => r=80/9
  slant height of cone= 10
  h=sqrt(10^2-(80/9)^2))
  h=(10sqrt17)/4
  r/h= (9sqrt17)/32
  r/h= 1.154> 3/4 but
• 12 years agoHelpfull: Yes(0) No(8)
• plz send this paper at sandipshaw1001@gmail.com
• 12 years agoHelpfull: Yes(0) No(1)
• s jain is right its 0.5
  
• 12 years agoHelpfull: Yes(0) No(2)
• please anyone explain this in detail with clear explanation??
• 12 years agoHelpfull: Yes(0) No(0)
• 3/5
  is it rght ?
  
• 12 years agoHelpfull: Yes(0) No(0)