50!/(16^15) Then What is the reminder?

• there should be 47 2s in 50!
  and we can write 16^15 as 2^47
  then there will remain 2^(60-47)in denominator
  now in numerator the last digit will be 5 because all the 2s has removed
  now 2^13=8192
  when numerator is divided by 8192 the remainder would be 1. because the last digit of denominator is 2..........
• 11 years agoHelpfull: Yes(20) No(2)
• ans-Remainder will be 1
• 11 years agoHelpfull: Yes(6) No(10)
• remainder is zero
• 11 years agoHelpfull: Yes(6) No(9)
• remainder is 0.becoz.we can write 16 ^ 15 as 4^30...50! will have many number of zeros in d last...its is divisible by 4...nd any power of 4 smaller tha 50!
• 11 years agoHelpfull: Yes(4) No(10)
• the remainder must zero since in 50! we have 4,8(4*2),16(4*4).... so em must zero
• 11 years agoHelpfull: Yes(2) No(2)
• amir, can you explain the solution in detail ??
• 11 years agoHelpfull: Yes(1) No(0)
• 2.63800207387794045616717376942373947775411307811737060546875 × 10^46
• 11 years agoHelpfull: Yes(1) No(0)
• ans should be 1 x 2^47, as explained by pankaj after cancelling 2^47 from numerator and denominator remainder is 1. bt in final answer we hv to multiply it by 2^47
  
• 10 years agoHelpfull: Yes(1) No(0)
• bhai 1 remainder hai....tukka laga ke mark zaroor karke aana..sabse zyada chance 1 ke hi lag rhe h
• 10 years agoHelpfull: Yes(1) No(0)
• reminder "0". because 50! is exactly devisable by 16^15.
• 10 years agoHelpfull: Yes(1) No(0)
• i dont trust anyone
  
• 9 years agoHelpfull: Yes(1) No(0)
• pls explain
  
• 11 years agoHelpfull: Yes(0) No(0)
• pls any one explain the problm clearly..
• 11 years agoHelpfull: Yes(0) No(0)
• i think remainder is 4. pls check
• 11 years agoHelpfull: Yes(0) No(0)
• 50!= 2^46 x 3^22 x 5^12 x 7^8 x 11^4 x 13^3 x 17^2 x 19^2 x 23^2 x 29x31x37x41x43x47
  16^15 = 2^60
  Therefore Ans = 2^-14 x 3^22 x 5^12 x 7^8 x 11^4 x 13^3 x 17^2 x 19^2 x 23^2 x 29x31x37x41x43x47
• 11 years agoHelpfull: Yes(0) No(4)
• ans : 1423
  reason :
  the value of 50! is 216105129892080882169214875191192738017616943359375
  the value of 16^15 is 8192
  so the remainder is 1423
• 10 years agoHelpfull: Yes(0) No(3)
• rajnikant hi solve kar sakta hai...
• 8 years agoHelpfull: Yes(0) No(0)
• actual solution is zero
• 8 years agoHelpfull: Yes(0) No(0)