Wipro Company

Value of -1~2[|2-x²|]dx, i.e. integration of the function |2-x²| over the interval -1 to 2.

Read Solution (Total 2)

Wipro Other Question

If f(x) =1-cos (1-cos x)/x 4 is continuous at f(0) then what is x how sud i prepare for wipro campus drive.....plz guide me frndz...if u hav ne idea abt it...:) is dere ne specific sites are dere from where i sud do prep for d campus drive...plz plz help me guys ...