Banu plays with two boxes seperately containing 25 red cards and 33 block cards and she allowed to move the cards between the boxes. She won the game by choose a box at random and a card at random from the chosen box the probability of getting a black card is minimized. Now,the question is to find that minimum probability.

solution:

• to minimise probability of black card, put 1 red card in one box and 24 red cards and 33 black cards in second box.
  then min prob of getting black card = 0*1/2 + 0.5 * 33/57 = 11/38
• 12 years agoHelpfull: Yes(43) No(2)
• move 24 red to black cards now probability to get black card
  because first box has no black so
  1/2 (for box chossen)
  (1/2)*0+(1/2)*(33c1/57c1)
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