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Quadratic Equations
a+b+c=0, then roots of ax^2+bx+c=0 is
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- roots of ax^2+bx+c=0 are (-b ± √(b^2- 4ac))/2a
since a+b+c=0, then substituting for any one of the unknown say, a = -(b+c)
we get roots as: 1 and (c/a) - 14 years agoHelpfull: Yes(19) No(2)
- ans is 1 and-c/b+c
- 14 years agoHelpfull: Yes(1) No(6)
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