a+b+c=0, then roots of ax^2+bx+c=0 is

• roots of ax^2+bx+c=0 are (-b ± √(b^2- 4ac))/2a
  
  since a+b+c=0, then substituting for any one of the unknown say, a = -(b+c)
  we get roots as: 1 and (c/a)
• 13 years agoHelpfull: Yes(19) No(2)
• ans is 1 and-c/b+c
• 13 years agoHelpfull: Yes(1) No(6)