find the number of zeroes in
1^1*2^2*3^3...48^48*49^49

• sorry i have done calculation wrong...
  250...
  5^5+10^10+15^15....45^45 will have zeroes
  total=5+10+15+20+50+30+35+40+45
  250
• 12 years agoHelpfull: Yes(23) No(8)
• 10+20+30+40 =100 zeros
  eg
  10^10= 10 zeros
  20^20=20 zeros
  
• 12 years agoHelpfull: Yes(6) No(2)
• ya it is 250
• 12 years agoHelpfull: Yes(5) No(3)
• pallavi ji: ANS/: 5+10+15+20+50+30+35+40+45=250 ///(5^5+10^10+++45^45)
  WHEN U multiply 1^1***5^5 will get d 5 zero bcz 1*2*3*4*5=120 has 1 zero in d last so 5*1=5 nd similarly 6***10 has 10*1= 10 so up to no 20).bt 21*22**25 hs 2 zero in last so just double that of actual value i.e 25*2=50. nd so on. last 4 no 46,47,48,49 multiplication can't give any zero so neglect these nos. ys u need calculator to check sm time tcs allowe cator, hope u got it ....pallavi
• 12 years agoHelpfull: Yes(5) No(0)
• But nitin here the series is multipled not added!!!
• 12 years agoHelpfull: Yes(4) No(0)
• m agree with paridhi. . hay you all sayin ans 250.
  please xplain how ?? unable to undrstand the logic.
• 12 years agoHelpfull: Yes(4) No(0)
• 2 ND Approach-
  count total no of pow of 5 nd sum is d answer.i.e 5^5+(10=5*2)^10+(15=5*3)^15+...+(25=5*5)^25 means 5^50+....+(45=9*5)45= 5+10+15+20+50+30+35+40+45=250
• 12 years agoHelpfull: Yes(4) No(0)
• 250...
  5^5+10^10+15^15....45^45 will have zeroes
  total=5+10+15+20+50+30+35+40+45
  200
• 12 years agoHelpfull: Yes(3) No(3)
• 13 zeros should be the answer
  because after squaring number having 5 at end oy 10 will give 0.
  number with 5 at end will be (5*5)=25, (15*15), (25*25),(35*35,(45*45)
  number with 0 at last will give 2 zero!!ie 10,20,30,40
• 12 years agoHelpfull: Yes(1) No(9)
• 5+10+15+20+50+30+35+40+45= 250
  ans is 250
• 12 years agoHelpfull: Yes(1) No(0)
• how can u add 5^5? It wont contribute any 0.. 5x5x5x5.. always give unit digit 5, never 0.. same case with 15, 25, 35, and 45.
  so I guess, answer will be 100.. (10+20+30+40)
• 12 years agoHelpfull: Yes(1) No(1)