The sum of the digits of a three digit number is 17, and the sum of the squares of its digits is 109. If we subtract 495 from the number, we shall get a number consisting of the same digits written in the reverse order. Find the number.
a. 773
b. 683
c. 944
d. 863

• ans>863
  8+6+3=17
  8*8+6*6+3*3=109
  863-495=368
• 9 years agoHelpfull: Yes(4) No(1)
• answer is D
  8+6+3=17
  8^2+6^2+3^2=109
  863-495=368
• 9 years agoHelpfull: Yes(1) No(1)
• For this question we have to look in the given options.
  here see the option C.
  In the question it is said that if we subtract 495 from the number,we shall get a number consisting of the same digits written in the reverse order
  944-495=499
  499 is reverse of 944.
  So,the option c is correct.
• 9 years agoHelpfull: Yes(1) No(1)
• x+y+z=17
  x^2+y^2+z^2=109
  (x+y+z)^2=x^2+y^2+z^2+2(xy+yz+zx)
  (17)^2=109+2(xy+yz+zx)
  xy+yz+zx=90
  by verifying given options the answer is 683
  6*8+8*3+3*6=90
• 9 years agoHelpfull: Yes(0) No(1)
• go from ans side 8^2+6^2+3^2=109
• 9 years agoHelpfull: Yes(0) No(1)