2 74 2 2048 2 2n what is the value of n so that sum will be perfect square

since, (a+b)^2=a^2+b^2+2ab
2^74+2^2n+2^2048=(2^37)^2+(2^n)^2+2^2048
2*(2^37)*(2^n)=2^2048
2^(1+37+n)=2^2048
since base are same ,equating powers,we get
1+37+n=2048
38+n=2048
n=2010
11 years agoHelpfull: Yes(16) No(3)
iam sorry 2010
11 years agoHelpfull: Yes(5) No(2)
(2^34)^2 + 2*2^34*2^n+(2^n)^2 compare with a^2+2ab+b^2
then 35+n=2048 = n=2013
11 years agoHelpfull: Yes(4) No(14)
2011
n can be any odd no.
11 years agoHelpfull: Yes(3) No(7)
2^74=(2^34)^2
2^2n=(2^n)^2
2^74+2^2048+2^2n ----------1
IF(2^34)^2+ 2.2^34.2^n+ (2^n)^2 -------------2
=(2^34+2^n)^2 so
from equn 1 &2 2.2^34.2^n must be equal to 2^2048
so (34+1+n)=2048 so n=2048-35=2013(ANS)
11 years agoHelpfull: Yes(2) No(9)
ans is 2010

(a+b)^2 = a^2 + 2*a*b + b^2

a^2= (2^37)^2 = 2^74
b^2= (2^2010)^2 = 2^4020
2*a*b = 2* 2^37 * 2^2010= 2^2048
11 years agoHelpfull: Yes(2) No(1)
sai ji aap hamesa confusion m kyun rehti h?
11 years agoHelpfull: Yes(2) No(0)
(A+B)^2=A^2+B^2+2*A*B
(2^37)^2+(2^n)^2+2*(2^37)*(2^2010)AS SAME AS GIVEN EQ.
SO n=2010 ( 2048=37+1+2010)
11 years agoHelpfull: Yes(1) No(1)
correct ans is 2013..
11 years agoHelpfull: Yes(0) No(9)
correct ans 1699
11 years agoHelpfull: Yes(0) No(1)

2^74+2^2048+2^2n what is the value of n so that sum will be perfect square