1st 44 int are written in order to form large no. N=123456............424344. What is the remainder when N is divided by 45?

• 12345.....424344 = (1234...424290) + (54)
  1st part is completly divisble by 45 and aftr dividng 54 by 45 we get 9 remaindr
  remainder is = 9
• 12 years agoHelpfull: Yes(15) No(10)
• When we add digits from 1+2+3+4.....9 = 45
  Now add digits 1+0+1+1+1+2+1+3......1+9 = 10+45 = 55
  Now add digits 2+0+2+1+2+2+2+3......2+9 = 20+45 = 65
  Now add digits 3+0+3+1+3+2+3+3......3+9 = 30+45 = 75
  Now add digits 4+0+4+1+4+2+4+3+4+4 = 4*5+10 = 30
  Now add 75+65+55+45+30 = 270
  Factors of 45 are 5 and 9
  270 is divisible by 9 ...... Hence if we divide the quotient ,got by dividing by 9 by 5 we will get , Answer as 4 .....
• 11 years agoHelpfull: Yes(2) No(5)
• plz explain...how the first part is divisible by 45
• 12 years agoHelpfull: Yes(0) No(3)
• just 45*2=90 splited as (90+54=144)
• 12 years agoHelpfull: Yes(0) No(2)
• We dint get any remainder....
• 10 years agoHelpfull: Yes(0) No(1)