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Numerical Ability
Time Distance and Speed
A and B are running around a circular track of length 120 meters with speeds 12 m/s and 6 m/s in the same direction. When will they meet for the first time?
a)25 b)30 c)10 d)20
Read Solution (Total 10)
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- 20 minutes
- 12 years agoHelpfull: Yes(38) No(1)
- whenever two people r running in same direction and they meet for first time=total distance/relative speed;
same direction s1-s2;opposite direction s1+s2;
120/(12-6)=20 - 12 years agoHelpfull: Yes(31) No(2)
- they are moving in same direction so (s1-s2)
relative speed =distanace/time
time=120/(120-60)=20 sec. - 12 years agoHelpfull: Yes(7) No(1)
- a covers 1 rond in 10 min b covers 1 round in 20min and in 20 min a covers 2 round so after 20 min they meet
- 12 years agoHelpfull: Yes(2) No(1)
- in 40 second they will meet first time.
- 12 years agoHelpfull: Yes(0) No(30)
- ya...shalini pasala is right , and sorry , actually i was trying to post my apology from last day but i was unable.
- 12 years agoHelpfull: Yes(0) No(0)
- a will take 10 sec while b will take 20 sec to compete path....so the min time on which they meet will be LCM of 10 and 20 which is 2o.......so option d is correct
- 12 years agoHelpfull: Yes(0) No(0)
- ans:20
tp=dist/relative speed
tp=120/12-6 - 12 years agoHelpfull: Yes(0) No(1)
- answer is 20....
A for 1 second=12m
then he will cover 120m in 10 seconds.
b for 1 second =6m
then he will cover 120m in 20 seconds.
at that time A will complete his 2nd round nd B will complete his first round and they will meet. - 9 years agoHelpfull: Yes(0) No(0)
- Distance=120,speed=12-6=6m/so,T=D/S
=120/6=20 - 6 years agoHelpfull: Yes(0) No(0)
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