Infosys
Company
Numerical Ability
Time and Work
There are two taps, which are used to fill the tank and one tap to empty the tank. First tap fill the tank in 10 min., while the second takes quarter of an hour to fill the tank if both are operated independently.Third tap is capable of emptying the tank in seven and a half minutes. If all the taps are opened simultaneously how long (if ever) will it take for the tank to get filled completely?
Read Solution (Total 5)
-
- Pipe A fills the tank in 10 min
Pipe B fills the tank in 15 min
Pipe C empties the tank in 15/2 min
If all the three opened simultaneously then in 1 min
1/10 + 1/15 - 2/15 of the tank will be filled
that means 1/30 th of the tank will be filled in 1 min
So it will take 30 minutes to fill the tank completely if all three pipes opened - 10 years agoHelpfull: Yes(4) No(0)
- Tank will fill in 30 min
IN 7 and half min:
1st tab fill the tank 75%
2nd tab fill the tank 50%
3rd tab empty the tank 100%
Remaining 25% in 7.5 min
100% = 7.5 * 4 = 30 min.
- 14 years agoHelpfull: Yes(2) No(0)
- 30 min.
- 14 years agoHelpfull: Yes(1) No(0)
- 30 minutes.
- 14 years agoHelpfull: Yes(0) No(0)
- Ans : 30 minutes
v/10 + v/15 - v/7.5 = v/30 - 14 years agoHelpfull: Yes(0) No(0)
Infosys Other Question