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1(1!)+2(2!)+3(3!)+....+2010(2010!)+2011(2011!)+2012(2012!)=?
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- 1(1!)+2(2!)=5 ie 3!-1
1(1!)+2(2!)+3(3!)=23 ie 4!-1
1(1!)+2(2!)+3(3!)+.............+2012(2012!)=2013!-1 - 12 years agoHelpfull: Yes(39) No(1)
- Let n=2012 =>n*n!=(n+1)!-n! =>2!-1!+3!-2!+4!-3!+---------2013!-2012!
Cancel out the + and neg no. you will get 2013!-1. - 12 years agoHelpfull: Yes(7) No(0)
- n(n!)=(n+1-1)n!=((n+1)n!-n!)
=(n+1)!-n!
=>2!-1!+3!-2!.....2012!-2011!+2013!-2012!=2013!-1 - 12 years agoHelpfull: Yes(7) No(0)
- (2!-1!)+(3!-2!)+(4!-3!)....(2012!-2011!)+(2013!-2012!)
=2013!-1! - 12 years agoHelpfull: Yes(2) No(1)
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