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If a and b are the roots of the equation x^2-6x+6=0 , then the value of a^2+b^2 is?
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- sum of the roots= -b/a=6.
product of the roots=c/a=6.
a^2+b^2= (a+b)^2-2ab=6^-2*6=24. - 11 years agoHelpfull: Yes(58) No(5)
- sorry @Geetha u r right..
from formula.
-b+-sqrtb^2-4ac/2a..(1)
the eq is x^2-6x+6=0
then put value of a,b,c in eq 1..
then solve a=3+sqrt3 & b=3-sqrt3
then a^2+b^2 is 24.. - 11 years agoHelpfull: Yes(3) No(0)
- pls put options also
- 11 years agoHelpfull: Yes(2) No(3)
- 36 is answer roots are (3+sqr3) and (3-sqr3) solve it answer is 36
- 10 years agoHelpfull: Yes(2) No(0)
- sorry my answer is 24 is wrong..
the right answer is a^2+b^2 is 22 - 11 years agoHelpfull: Yes(1) No(11)
- a=2 b=3 2^2+3^2=13
- 11 years agoHelpfull: Yes(1) No(11)
- we solve this equation..then roots:-
a=3+sqrt2
b=3-sqrt2
then a^2+b^2 is 26... - 11 years agoHelpfull: Yes(0) No(11)
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