TCS
Company
Numerical Ability
Number System
If a number 272758 and 273437 is divided by N then they give remainder as 13 and 17 respectively. find the sum of digits of number N.
Read Solution (Total 8)
-
- since 13 n 17 are remainders
thus subtracting gives 272758-13=272745 n 273437-17=273420
then GCF of 272745,273420 gives 45
ANS:4+5=9 (easy to find gcf,N may be less than 45 also,GO ACCORDING TO THE OPTIONS) - 12 years agoHelpfull: Yes(42) No(2)
- find HCF of
272758-13 and 273437-17,,,
HCF will be 45
Hence, 4+5,,,
ans is 9 - 12 years agoHelpfull: Yes(10) No(1)
- hey frnz..ye ques mere aptitude me aya hai ques repeat ho rey hai believ me i cleared the apt..
- 12 years agoHelpfull: Yes(6) No(3)
- ANSWER should be 1+5 = 6 .
because given data is 13 and 17 as remainder so minus both of no. from 272758-13=272745 and 273437-17=273420 so now suppose x,y are answer and diviser is N for both no.
272745/n=x----(1)
273420/n=y---(2)
compare both equations.
and x/y=18183/18228
so now these two are values of no when it divided by same no N .
for find value of N is 272745/273420 is divide by 18183 and 18228 so no will be N=15 so sum of digit is N=1+5
N=6 - 12 years agoHelpfull: Yes(5) No(11)
- hey sakshi congrats
ans to bta do - 12 years agoHelpfull: Yes(5) No(1)
- Here it is not unique solution
272758 -13 = 272745 and 273437- 17 =272720
272745 and 272720 are divisible by 1,3,9,5,15,45
So Sum of the digits is 1 or 3 or 5 or 9 or 6. (4+5 =9)
N is not unique. It is not mentioned greatest 2 digit number.
272720 is divisible by 4 and 7 but 272745 is not divisible by 4 and 7 it is divisible by 11. Here I have considered all factors - 11 years agoHelpfull: Yes(1) No(0)
- its sure that answer has to be bigger than 17 as we getting it as remainder
other wise if ans is like 9 ,6 etc then why don't they go for more simplification
17mod9=8
13 mod 9=4
- 11 years agoHelpfull: Yes(1) No(0)
- 272758-13=272745
273437-17=273420
now calculate hcf of 272745 & 273420 which will be 15
sum of digits will be 1+5=6. - 8 years agoHelpfull: Yes(0) No(0)
TCS Other Question