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the milk and water in vessels a and b are in ratio 4:3 and 2:3.in what ratio the liquids in both vessels are mixed to obtain a new mixture in vessel c contain half milk and half water ?
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- let the total liquid in container = x
quantity of A in container 1 = 4x/7
quantity of B in container 1 = 3x/7
quantity of A in container 2 = 2x/5
quantity of B in container 2 = 3x/5
new ratio of A and B = 1/2:1/2
let quantity container 1 mix = n
let quantity container 2 mix = m
=>now Quantity of A = 4xn/7+2xm/5 = x(4n/7+2m/5)
=>now Quantity of B = 3xn/7 + 3xm/5 = x(3n/7 + 3m/5)
As new quantity of A and B are equal
=> 4n/7+2m/5 = 3n/7 + 3m/5
=> n/7= m/5
=> n/m =7/5 - 12 years agoHelpfull: Yes(33) No(1)
- ... 7:5..
- 12 years agoHelpfull: Yes(7) No(2)
- 7:5
Use the method of allegation in mixtures - 12 years agoHelpfull: Yes(6) No(1)
- my ans is ratio 1:1
- 12 years agoHelpfull: Yes(1) No(12)
- ans is 7/5
- 12 years agoHelpfull: Yes(1) No(0)
- Pls expkain @amit
- 12 years agoHelpfull: Yes(0) No(2)
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