A man working in MNC, for going office he used daily local trains which was routed in the morning. There was two type of trains one was type A and other was type B . The frequency of both trains was 10 minutes if one trains (type A )start at 5:00 AM and second (Type B)start at 5:02 A.M and after that it continuously running in every 10 minutes .A Man went to the station at random time in the morning what is the number of chance he got type A train mostly rather than type B trains.

• For getting train B, he has got only two minutes time i.e. only if he arrives in between 5:00 AM and 5:02 AM but if he comes in between 5:02 and 5:10 i.e 8 minutes time, he will get train A.
  so chances of getting trains A and B are in ratio of 8:2 or 4:1.
• 11 years agoHelpfull: Yes(62) No(2)
• answer is 1/2,,,,,,,,,,,,,bcoz in 1 hour the chance of getting type A train is 6 and chance of getting type B train is 6,,,,so the chance of getting type train is,,,,,,,,,,6/(6+6)=1/2
• 11 years agoHelpfull: Yes(2) No(15)
• the ratio of times is 2:10=1:5
  for type A,the probability is 1/6=0.1666
• 11 years agoHelpfull: Yes(1) No(5)