IBM
Company
Logical Reasoning
Number Series
3,8,12,48,29 ?
Read Solution (Total 6)
-
- 1^2+2=3
2^2*2=8
3^2+3=12
4^2*3=48
5^2+4=29
6^2*4=144 - 9 years agoHelpfull: Yes(67) No(2)
- 1*1+2=3
2*2*2=8
3*3+3=12
4*4*3=48
5*5+4=29
6*6*4=144 - 9 years agoHelpfull: Yes(5) No(2)
- Ans:144
1^2+2=3,
2^2*2=8,
3^2+3=12,
4^2*3=48,
5^2+4=29,
6^2*4=144. - 7 years agoHelpfull: Yes(1) No(0)
- can u explain this answer
- 9 years agoHelpfull: Yes(0) No(1)
- Plz send both aptitude, English question with answer to kothaimca25@gmail.com
- 9 years agoHelpfull: Yes(0) No(4)
- alternate numbers 8,48,
is multiple of 6
then 8*6=48
48*6=288
ans is 288 - 9 years agoHelpfull: Yes(0) No(6)
IBM Other Question
46080, 3840, 384, 48, 8, 2, ?
A. 1
B. 1⁄64
C. 1⁄8
D. None of these
In A,B,C are having some marbles with each of them. A has giben
B and C the same number of marbles they already have to each of them.
then, B gave C and A the same no. of marbles they have, then C gave
A and B the same no. of marbles they have. At the
end A,B,and C have equal no. of marbles.
(i) If x,y,z are the marbles initially with A,B,C respectively.
then the no of marbles B have at the end
(a) 2(x-y-z) (b) 4(x-y-z) etc.
(ii)If the total no. of marbles are 72, then the no. of marbles with A at the starting
a. 20 b. 30 c. 32
3.