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Maths Puzzle
(1941^3781)*(1961^4181). wat r d last 2 digits of the result
a)12
b)22
c)42
d)44
Read Solution (Total 3)
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- 1941^3781 last two digits=41
1961^4181 last two digits=61
41*61=2501 - 12 years agoHelpfull: Yes(13) No(2)
- is the ans 01..
- 12 years agoHelpfull: Yes(4) No(3)
- is this a dummy question???????
- 12 years agoHelpfull: Yes(1) No(0)
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