M4maths
Maths Puzzle
Category
If k, k^2 and (2k+1) are in arithmetic progression then k-(1/2k) is?
Read Solution (Total 1)
-
- k k^2 and 2k+1 are in AP
k^2 = (k+2k+1)/2
2k^2 = 3k+1
2k^2 - 1 = 3k
(2k^2 - 1)/2k = 3k/2k = 3/2
k - (1/2k) = 3/2
- 9 years agoHelpfull: Yes(0) No(0)
M4maths Other Question