Ram leaves to his office 30 min late as compared to other days.He travel with speed 25% less than other days speed and finally he reach office 50 min late.what is the time taken by ram in normal days.
Ans-60 min

• ans = 60 mins
  AS:
  let speed at normal days be x km/h
  total distance be D km
  time taken D/x.....................(1)
  speed on that day becomes 3x/4
  time taken D/(3x/4)=4D/3x.............(2)
  (2)-(1) gives 20 mins
  from this we get D=x
  hence,time taken D/x=1 hour=60 min
• 12 years agoHelpfull: Yes(17) No(2)
• Let usual speed of Ram be x km/hr and distsnce d km between home n office.Speed on dat day =x-(25/100)x =3x/4.So difference of time taken by him to reach office between these two days =50-30=20min(30 is subtracted as he left for office 30 min late and 50 is taken as he was 50 min late).So 4d/3x - d/x =20/60 ,on solving (d/x) comes 1 i.e 1 hr is the time taken in normal days by Ram.
• 12 years agoHelpfull: Yes(6) No(0)
• let normal time
  s=d/t
  3s/4=d/t+20
  4/3=t+20/t
  4t=3t+60
  t=60
• 12 years agoHelpfull: Yes(2) No(0)