When a number divided by D leaves remainder of 8 and when by 3D leaves remainder of 21.what is the remainder left,when twice the number is divided by 3D.

• suppose the number is N and the quotient is Q and Q'.
  now, N=DQ+8 ..(1)
  N=3DQ'+21 ...(2)
  
  now as we multiply the (1) by 3 and subtract it from (2) we would get
  2N=3D(Q-Q')+3
  hence the remainder is 3.
• 11 years agoHelpfull: Yes(86) No(4)
• 60/13 rem = 8 , 60/39 rem =21 , 120/117 rem = 3...ans 3
• 11 years agoHelpfull: Yes(9) No(1)
• EQUTION FO THESE TYPE OF QUESTIONS IS
  
  NUMBER=DIVIDEND*Q+R
  
  so
  let no be x
  
  x=dq+8......1
  x=3dq'+21....2
  
  now multiply the eq 1 by 3
  we get
  
  3x=3dq+24....3
  
  now subtract 3 from 4
  
  we get
  
  2x=3d(q-q')+3
  
  so ans is 3
  
  
• 11 years agoHelpfull: Yes(5) No(0)
• sorry frend by mistake earlier answer ws wrong correct is 3
• 11 years agoHelpfull: Yes(2) No(3)
• @amit-how did u assume a number ie 60???
• 11 years agoHelpfull: Yes(2) No(0)
• options ????
  
• 11 years agoHelpfull: Yes(0) No(11)
• reminder will be 6..
• 11 years agoHelpfull: Yes(0) No(15)