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In the set{1,2,3,4,5} any 3 random number choosen can be same numbers wat is the probability so tat a*b+c is even
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- given set is 1,2,3,4,5
our aim is to find probability so that a*b+c should be even
a*b+c gives even number when two odd numbers is added
i.e, odd no+odd no gives even no.
and even no + even no gives even no
so lets consider case1:odd+odd=even (a*b) is odd and c is odd
now a*b gives a odd no when a and b are odd no.
probability of odd number from given set=3 by 5
so case1 gives the prob as (3 by 5)*(3 by 5)*(3 by 5)=(27 by 125)........1
case2: even+even=even
prob of even no from the set=2 by 5
a*b is even and c is even (three cases are possible)
a(odd) b(even) c(even)= (3 by 5)*(2 by 5)*(2 by 5)and
a(even) b(odd) c(even)= (2 by 5)*(3 by 5)*(2 by 5)and
a(even) b(even) c(even) = (2 by 5)*(2 by 5)*(2 by 5).
so totally (27+12+12+8)by 125......ans
- 12 years agoHelpfull: Yes(35) No(1)
- 59/125....
- 12 years agoHelpfull: Yes(6) No(1)
- ans=59/125
- 12 years agoHelpfull: Yes(2) No(1)
- even+even=even
odd+odd=odd
(2*2+2)=6
(3*3+3)=12 des r choices
total ways of selecting=5*5*5=125
total ways =18/125 - 12 years agoHelpfull: Yes(1) No(13)
- ans is 47/125
- 12 years agoHelpfull: Yes(1) No(4)
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