Raju can do a piece of work in 10 days..vicky 12days,tinku 15 days..day all start the work together,but raju leaves aftr 2 days,vicky leaves 3 days before the work is completed..how many days work is completed?
7,5,9,6

• raju+vicky+tinku one day work = (1/10)+(1/12)+(1/15)= 1/4
  now for 2 days together work done= 2*(1/4)= 1/2
  ......now work done by tinku in last 3 days alone=(3/15)=(1/5)
  remaining work= 1-(1/2 + 1/5)= 3/10
  ....now vicky+tinku one day work=(1/12)+(1/15)=9/60
  therefore 3/10 work will be done by both of them in= (60/9)*(3/10)= 2 days
  
  now answer= 2days(as got from above; it is days required to do rem. work)+ 3days(when vicky leaves)+2days(raju leaves)=7 days ans.
• 12 years agoHelpfull: Yes(69) No(2)
• let work be completed in x days...
  so
  2/10+x-3/12+x/15=1 (sort-cut method)
  after solving this ...we get the value of x=7 ans..
  
• 9 years agoHelpfull: Yes(14) No(2)
• ans is 7.
• 12 years agoHelpfull: Yes(5) No(3)
• R=10%
  V=8.33%
  T=6.66%
  TOGETHER WORK FOR 2 DAYS SO 2*(10+8.33+6.66)=50%DONE
  FOR LAST 3 DAY ONLY TINKU WORKS THUS 3*6.66=19.33%DONE
  REMAINING 30%WILL DONE BY V AND T THUS 30/(8.33+6.66) =2DAYS
  THUS 2+3+2=7DAYS
• 9 years agoHelpfull: Yes(4) No(0)
• raju 10days
  vicky 12days (common multiple of that numbers is no of total units of work)
  tinku 15days
  the total work is 60 units .
  raju do 6 units work in 1 day,
  vicky do 5 units work in 1 day,
  tinku do 4 units work in 1 day.
  all started together and work for two days so,work is 2(6+5+4)=30.
  remaing 30 units.
  vicky and tinku do it in 4 days but vicky leaves 3 days before so vicky work only one day after raju left.
  no of units completed=39 units(i.e 5+4=9,so total units 39 remaing 21 units)
  21 units are comleted by tinku in 6 days so
  the answer is all worked in 2days,vicky&tinku worked in 1 day,tinku worked for 6 days ,i.e9days.
• 8 years agoHelpfull: Yes(4) No(5)
• LCM 10 12 15 = 60
  R-6; V-5; T-4
  2(6+5+4)=30
  Vicky leaves 3 days before the work is completed that means Tinku worked for last 3 days alone so 3(4)=12
  Now, 60-30-12=18
  that means Vicky and Tinku did 18 work but they can do only 9 work in a day =>they worked for 2 days
  So total required days=2+3+2=7
• 6 years agoHelpfull: Yes(4) No(0)
• ans is 7 ,for one day raju=1/10,vicky=1/12,tinku=1/15 so al togethr in one day is =1/4,so for 2 days it is =1/2 acc to question raju leves and the remaing wrk is 1-1/2=1/2 ,now tinku and vicky can do togeher can do one wrk in 60/9 days so half wrk can be done in 60/18=10/3 days, so for one day wrk done is 3/10 so for 3 days 9/10 is done and vicky levs remainng wrk is 1/10 whch is done by tiku for 1 day 1/15 wrk is done,for doing 1/10 1.5 days .so total num of days is 2+3+1.5=7 days (approx)
  
• 12 years agoHelpfull: Yes(2) No(4)
• ans is 7 ,for one day raju=1/10,vicky=1/12,tinku=1/15 so al togethr in one day is =1/4,so for 2 days it is =1/2 acc to question raju leves and the remaing wrk is 1-1/2=1/2 ,now tinku and vicky can do togeher can do one wrk in 60/9 days so half wrk can be done in 60/18=10/3 days, so for one day wrk done is 3/10 so for 3 days 9/10 is done and vicky levs remainng wrk is 1/10 whch is done by tiku for 1 day 1/15 wrk is done,for doing 1/10 1.5 days .so total num of days is 2+3+1.5=7 days
• 12 years agoHelpfull: Yes(1) No(2)
• one day work of R=1/10,V=1/12,T=1/15
  one day together work=1/10+1/12+1/15=1/4
  they all work for 2 days so 2 days together work =2*(1/4)=1/2 (2 DAYS)
  than raju leaves and
  vicky lvs 3 days before so 3 days work done by only tinku so find tinku 3days work
  tinku 1 day work =1/15
  tinku 3days work =3*(1/15)=1/5 (3 DAYS)
  Remaining work=1-(sum work complete by 3 and tinku)
  i.e=1-(1/2+1/5)=3/10
  3/10 work done by vicky and tinku
  T+V one day work =1/12+1/15=3/20
  1 work done in 20/3 days
  3/10 work =3/10*20/3=2 DAYS
  TOTAL TIME TAKEN=2Days(R+v+T)+3 Days(TINKU)+2 Days (TINKU+ Vicky)=7 Days
  ans=7 days
  
• 9 years agoHelpfull: Yes(1) No(0)