(44^44)/8^n what is the max vale of n??

• (44^44)/8^n= (2^88)*(11^44)/8^n = 2*(8^29)*(11^44)/8^n
  
  for integer value of (44^44)/8^n, max value of n is 29.
• 12 years agoHelpfull: Yes(35) No(4)
• 44^44=(4*11)^44
  thus power of 2 is 88 as power of 4 is 44
  now 8^n=2^3n
  thus for 44^44 to be completely divisible by 8 we need powers to be equal
  thus 3n=88
  thus n=[88/3] where [] stands for integral part
  thus integral part of 88/3 is 29
  thus n can be atmost 29
• 12 years agoHelpfull: Yes(8) No(0)
• n=29 right ans
  
• 12 years agoHelpfull: Yes(4) No(2)
• plz explain properly
• 12 years agoHelpfull: Yes(2) No(2)
• 29 is correct
  
• 12 years agoHelpfull: Yes(1) No(3)
• 29 correct
  
• 12 years agoHelpfull: Yes(1) No(2)