How many kgs. of wheat costing Rs.4.8 per kg must be mixed with 66 kg of rice costing Rs. 6.40 per kg so that 20% gain may be obtained by selling the mixture at Rs. 7.20 per kg?
22 kg

• Let there will be xkg of wheat.
  CP of mixture = 100*7.2/120 = Rs 6 per kg
  A/Q
  total cost before mixing=total cost after mixing
  (66+x)*7.2=66*6.4+4.8x
  so x=22;
  
• 11 years agoHelpfull: Yes(20) No(5)
• see, 4.80 6.40
  
  7.20
  
  1.20 3.60
  (Write the difference crosswise)
  so,the ratio of mixing is=1.20:3.60=1:3
  so, 3/4=66 i,e 1/4=66/3=22
  so,22Kg wheat was mixed.(Ans)
• 11 years agoHelpfull: Yes(16) No(4)
• 22 kg
  
  SP of mixture = Rs 7.2 per kg
  CP of mixture = 100*7.2/120 = Rs 6 per kg
  
  By method of alligation
  Ratio of Rs 4.8 kg wheat and Rs 6.4 kg rice to get a mixture of price of Rs 6 per kg will be
  (6.4-6): (6-4.8) i.e. 0.4 :1.2 or 1:3
  so 66 kg of rice of Rs 6.4 per kg should be mixed with 66*1/3 = 22 kg wheat costing Rs 4.8 per kg.
• 11 years agoHelpfull: Yes(8) No(3)
• its a very simple problm of alligations and mixures in rs aggrwl...just see examples of dat...nd u'll be the master of these type of questions..
  
  
• 11 years agoHelpfull: Yes(5) No(1)
• ans is 22 kg
  
• 11 years agoHelpfull: Yes(2) No(1)
• see, 4.80 6.40
  /
  7.20
  /
  1.20 3.60
  (Write the difference crosswise)
  so,the ratio of mixing is=1.20:3.60=1:3
  so, 3/4=66 i,e 1/4=66/3=22
  so,22Kg wheat was mixed.(Ans)
• 11 years agoHelpfull: Yes(2) No(1)
• ans is 22 kg
  
• 11 years agoHelpfull: Yes(1) No(1)
• let the required weight be x...so required cost be 4.8x + (6.4*66)....now this is equal to 6(x+66)...since 20% gain implies 120/100 is for 7.2(x+66)...if we calculate for normal price with out gain...then for 100/100 it is 6(x+66)
  so...6(x+66) = 4.8x + (422.4)...so x=22
• 11 years agoHelpfull: Yes(1) No(0)
• using alligation
  (7.20-6.40):(7.20-4.8)=.8 : 2.4
  (x/66)=(.8/2.4)
  x=66/3
  x=22 ans
• 11 years agoHelpfull: Yes(1) No(0)
• how plz explain
• 11 years agoHelpfull: Yes(0) No(2)
• how explain it na
• 11 years agoHelpfull: Yes(0) No(2)
• let the required weight be x...so required cost be 4.8x + (6.4*66)....now this is equal to 6(x+66)...since 20% gain implies 120/100 is for 7.2(x+66)...if we calculate for normal price with out gain...then for 100/100 it is 6(x+66)
  so...6(x+66) = 4.8x + (422.4)...so x=22
• 11 years agoHelpfull: Yes(0) No(0)