TCS
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Logical Reasoning
Coding Decoding
A man asks 5 people to make a guess about the amount of money in his pocket which is less than 50.
A guess that the amt is a multiple of 10..
B guess that the amt is a multiple of 12..
C guess that the amt is a multiple of 15..
D guess that the amt is a multiple of 18...
E guess that the amt is a multiple of 30
Which of the following guesses are correct?
a.AE
b. AB
c. BC
d. DE
Read Solution (Total 9)
-
- AE:30 is multiple of both 10 and 30 which is less than 50. ... possible answer.
AB: there is no multiple of 10 and 12 less than 50. ..... not possible answer.
BC: Same logic as that of AB. ..... not possible answer.
DE: Same logic as that of AB. ..... not possible answer.
Hence answer is AE. - 12 years agoHelpfull: Yes(44) No(0)
- AE:lcm of both 10 and 30 is 30 which is less than 50. ... possible answer.
AB: lcm of 10 and 12 is 60> 50. ..... not possible answer.
BC: lcm of 12 and 15 is 60> 50. ..... not possible answer.
DE: lcm of 18 and 30 is 90> 50. ..... not possible answer.
Hence answer is AE. - 12 years agoHelpfull: Yes(32) No(0)
- by the options provided only the option a is satisfied i.e AE and the amount with him is exactly 30 rupees as 30 is less hen 50 and also a multiple of both 10 and 30
- 12 years agoHelpfull: Yes(4) No(1)
- a.AE as 10 and 30 both are multiple of 30 which is less den 50
- 12 years agoHelpfull: Yes(2) No(1)
- AE is correct this the only possible combination out of given options
- 12 years agoHelpfull: Yes(2) No(0)
- i think this question is uncompleted...
- 12 years agoHelpfull: Yes(1) No(4)
- answer is a...i.e.,AE...because...amount is less than 50..to satisfy that in the given options AE, is true that lcm of 10,30 is 30..which is below 50...
- 12 years agoHelpfull: Yes(1) No(0)
- ae
mutiple
- 12 years agoHelpfull: Yes(1) No(2)
- option d)AE
- 9 years agoHelpfull: Yes(0) No(1)
TCS Other Question
1,5,13,27,48,?
Question data are wrong.
According to ours consideration
The 2nd condition given is wrong it should be two more than the age of other two children...
Let the three grandchildren age be a,b and c
Thus, a is youngest, c is eldest.
c = 3a.........(i)
c = 2+(a+b)..........(ii)
=> 3a = 2+a+b
=> 2a = 2+b
Thus, the ages are.....
a, 2a-2 , 3a.
Two of their difference is 3.
Thus, a- 2 =3 or a+2 =3 or 2a =3
a =5 or a =1 or a =3/2.
Thus ages are, 5,8,15
or , 1,0 3 (not possible). or 3/2, 1, 9/2 (not possible.).
The answer should be 15.