1! + 2! + 3! + ………………………+ 2730! = ?

can some one help me to solve this puzzle i need the general soln to solve these kind of puzzles

• sorry.. earlier answer posted was for some other kind of puzzle
  where we have
  1!*1 + 2!*2 + 3!*3 +.......+ n*n! = (n+1)!-1
  
  
• 12 years agoHelpfull: Yes(16) No(3)
• use this
  1!+2!+3!+..........+n!= (n+1)!-1
  1!+2!+3!= 4!-1
  so your answer would be 2731!-1
• 12 years agoHelpfull: Yes(7) No(20)
• i guess the formula was wrong. because if i apply for the smaller values its not working.
  
  1!+2!+3!+4!=????
  here n=4
  
  Apply formula (n+1)!-1
  
  (4+1)!-1
  
  120-1=119 But if we add individual it is 1+2+6+24=33....
  
  please tell me the logic to find the sum......
• 12 years agoHelpfull: Yes(2) No(1)
• sunil tell me how can i find 2731!..?
• 12 years agoHelpfull: Yes(0) No(2)
• sunil ans for that series which you told is (n+1)!-n! soo how can u say (n+1)!-1???? plz expl
• 12 years agoHelpfull: Yes(0) No(4)
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  #include
  int main()
  {
  int num,i,j,fact,sum=0;//variables
  printf("Enter the last number of series:n");
  scanf("%d",&num);//last number of series
  for(i=1;i
• 7 years agoHelpfull: Yes(0) No(0)
• #include
  int main()
  {
  int num,i,j,fact,sum=0;//variables
  printf("Enter the last number of series:n");
  scanf("%d",&num);//last number of series
  for(i=1;i
• 7 years agoHelpfull: Yes(0) No(0)