Three friends Mohit,Manohar and Prashant decided to share a lot of bananas. Each of them had half of the total plus half a banana in order. After each of them took their share twice, no bananas were left.
1.How many bananas were there?
2.How many bananas did Mohit get?
3.How many bananas did Manohar get?

• Total bananas=63
  Mohit have=36(32+4) Bananas
  Manohar have=18(16+2) bananas
• 12 years agoHelpfull: Yes(8) No(6)
• @Radhika & Saurabh-Dear,
  ther r 2 methods to solve dis type of qus.:
  1)go through options,which is a good choice
  2)(2^n)-1 is the formula
  
  here n is roatation
  according to question its twice means 2*3=6
  
  (2^6)-1=63
  now 4 mohit=(64/2)+4=36
  4 manohar=(64/4)+4/2=18
  
• 12 years agoHelpfull: Yes(7) No(0)
• mohit,manohar and prashant will have bananas in order x/2,x/4,x/8,x/16,x/32,x/64,
  also they will have 3 additional bananas. all these equals to x bananas . so ans is 192................ :)
• 12 years agoHelpfull: Yes(5) No(3)
• @Akhand: can u plzz explain it..
  
• 12 years agoHelpfull: Yes(2) No(1)
• (2^n)-1 is the formula
  
  here n is roatation
  according to question its twice means 2*3=6
  
  (2^6)-1=63
• 12 years agoHelpfull: Yes(2) No(0)
• plzz give d options ...
• 12 years agoHelpfull: Yes(0) No(1)
• @Akhand..please explain your solution
• 12 years agoHelpfull: Yes(0) No(0)
• @akhand...how u have found out the total no of bananas for mohit and manohar..?By the way ur ans is correct..:)please explain me the process for mohit and manohar
• 12 years agoHelpfull: Yes(0) No(0)