The sum of the three consecutive numbers of the four numbers A,B,C,D are 4613,4961,5010,5099.
Then what is the largest number among A,B,C,D.

• A+B+C=4631
  B+C+D=4961,
  C+D+A=5010,
  D+A+B=5099,
  after solving above 4 equ.we get:
  D-A=348
  D-C=486,
  D-B=397,
  In above 3 equ.RHS is+ve after substraction f A,C,B from D.
  SO D IS LARGEST NO.
• 12 years agoHelpfull: Yes(29) No(3)
• A+B+C=4613
  B+C+D=4961
  C+D+A=5010
  D+A+B=5099
  adding all equation 3(A+B+C+D)=19983
  =>A+B+C+D=6661
  A=1700
  B=1651
  C=1562
  D=2048
  therefore D is largest
• 12 years agoHelpfull: Yes(10) No(1)
• a+b+c=4613
  b+c+d=4961
  c+d+a=5010
  d+a+b=5099
  from eq 1 &2 d>a
  from eq 2&3 a>b
  from eq 3&4 b>c
  hence it is clear largest no is D ans
  
• 12 years agoHelpfull: Yes(6) No(0)
• a+b+c=4613
  b+c+d=4961
  c+d+a=5010
  d+a+b=5099
  d is larger
• 12 years agoHelpfull: Yes(1) No(0)