Only two candidates,Nitish and Lalu,contested the election of Patna parliamentary constituency.20% of the voters have not cast their vote and 120 votes have been declared as invalid.The winner,Nitesh,got 200 votes more than his opponent Lalu,thus he secured 41% of the votes out of the total votes.Percentage of votes of the defeated candidate of the total votes polled is:
A.38% B.41%
C.45%
D. 47.5%

• 20% votes are less , so total given vote = 80%.
  Out of which nitish got 41% so rest are = 39%
  
  Let votes of lalu = x ;
  so vote of nitish = x+200;
  rest vote = vote of lalu + discard votes ;
  = x + 120;
  Let total no of votes = t.
  So .. (x+200)*100/t = 41 . ...(1)
  and (x+120)*100/t = 39. ..... (2)
  
  By solving (1) nd (2)..
  we get t = 4000 , x = 1440.
  
  so total pulled vote = 80% of t = 3200.
  so defeted % = 1440*100/3200 = 45%... ans(C).
  
  
• 11 years agoHelpfull: Yes(31) No(5)
• ans cant be 45%. since 41% se less than 45%.percent of vote of won candidate wl be more than that of the defeated one. . n check the options only option a is in favour. .so without going through detailed calculation we can directly say that ans will be 38% :)
• 11 years agoHelpfull: Yes(15) No(11)
• @PALLAVI: ans is correct...
  here 45% is percent of votes of the defeated candidate of the total votes polled
  n 41% is percent of votes that nitesh got of the total no. of votes( polled+ not polled).
• 11 years agoHelpfull: Yes(7) No(4)
• somebody please provide clear solution ......
• 11 years agoHelpfull: Yes(6) No(4)
• abhishek was right i was wrong !
• 11 years agoHelpfull: Yes(4) No(0)
• abhishek was right i was wrong !
• 11 years agoHelpfull: Yes(4) No(0)
• abhishek was right i was wrong !
• 11 years agoHelpfull: Yes(3) No(0)
• abhishek was right i was wrong !
• 11 years agoHelpfull: Yes(3) No(0)
• abhishek was right i was wrong !
• 11 years agoHelpfull: Yes(3) No(0)
• abhishek was right i was wrong !
• 11 years agoHelpfull: Yes(2) No(0)
• abhishek was right i was wrong !
• 11 years agoHelpfull: Yes(2) No(0)