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if 5 dice are thrown then what is the probability of getting sum greater than 15?
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- (1,1,1,1,1,1)=1
(2,1,1,1,1),(1,2,1,1,1),(1,1,2,1,1),(1,1,1,2,1),(1,1,1,1,2)=5
(2,2,1,1,1),(1,2,2,1,1),(1,1,2,2,1),(1,1,1,2,2),(1,2,1,2,1),(1,1,2,1,2),(2,1,2,1,1)=7
(2,2,2,1,1),(1,2,2,2,1),(1,1,2,2,2),(2,1,2,2,1),(2,2,1,2,1),(1,2,2,1,2),(1,2,1,2,2)=7
(2,2,2,2,1),(1,2,2,2,2),(2,1,2,2,2),(2,2,1,2,2),(2,2,2,1,2)=5
(2,2,2,2,,2)=1
(3,2,2,2,2),(2,3,2,2,2),(2,2,3,2,2),(2,2,2,3,2),(2,2,2,2,3)=5
(3,3,2,2,2),(2,3,3,2,2),(2,2,3,3,2),(2,2,,2,3,3),(2,3,2,3,2),(3,2,3,2,2),(2,2,3,2,3)=7
(3,3,3,2,2),(2,3,3,3,2),(2,2,3,3,3),(3,2,3,3,2),(3,3,2,3,2),(3,3,2,2,3),(2,3,2,3,3),(2,3,3,2,3)=8
(3,3,3,3,2),(3,2,3,3,3),(3,3,2,3,3),(3,3,3,2,3),(2,3,3,3,3)=5
(3,3,3,3,3)=1
total=1+5+7+7+5+1+5+7+8+5+1=52
grater than=6^5-52=7776-52=7724.
probality of getting sum greater than 15=7724/7776
- 12 years agoHelpfull: Yes(9) No(7)
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- 12 years agoHelpfull: Yes(1) No(6)
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