if certain sum of money borrowed at 5% per annum simple interest amounts to rs1020 in 4yrs then the sum of money borrowed is?

• let p be the amt..
  (p*5*4)/100=1020-p =>p=850/-
• 11 years agoHelpfull: Yes(31) No(5)
• rs. 5100 is the ans......
• 11 years agoHelpfull: Yes(13) No(11)
• are this the recent question of tcs , from the indore(today) campus drive???
• 11 years agoHelpfull: Yes(4) No(2)
• sol is Rs 5100 solved with the help of SI
• 11 years agoHelpfull: Yes(4) No(8)
• let amount borrowed=x
  amount after 1 year=x+x*5*4/100
  1020=1.2x
  x=850
• 9 years agoHelpfull: Yes(1) No(1)
• SI=PIR/100
  1020=(X*5*4)/100
  X=5100
• 8 years agoHelpfull: Yes(1) No(0)
• Simple Interest (SI)=(P*T*R)/100
  1020=(P*4*5)/100
  then we will get P=5100
  
  to cross check our ans SI=(P*T*R)/100
  1020=(5100*4*5) /100
  1020=1020
  
• 10 years agoHelpfull: Yes(0) No(4)
• Let principle be Rs.x and Interest be Rs.y
  Amount= Principle +Interest
  =>1020=x+y ------1
  Interest=(P*R*T)/100
  =>y=(x*5*4)/100
  =>5y-x=0 1 -------2
  
  Solving eq 1 and 2, y=170
  from eq 1, x=1020-170=Rs. 850
  
• 9 years agoHelpfull: Yes(0) No(0)
• SI for 1 year =1020/4=255
  5%=255,
  money borrowed=255*20=5100(for 100%)
• 9 years agoHelpfull: Yes(0) No(0)
• 1020=(p*5*4)/100
  p=5100
  
• 9 years agoHelpfull: Yes(0) No(0)
• si=(ptr/100) so 5100
• 9 years agoHelpfull: Yes(0) No(0)
• (P)+(P*4*5/100)=1020
  by solving above equation we get P=850, which is the sum of money borrowed
• 9 years agoHelpfull: Yes(0) No(0)
• r= 5%
  pi+si= 1020
  t= 4yrs
  si= p*R*T/100
  si= p/5
  p=1020-p/5
  p=850
  
• 9 years agoHelpfull: Yes(0) No(0)
• i=p*t*r/100
  1020=p*4*5/100
  p=5100
• 9 years agoHelpfull: Yes(0) No(0)
• for those who are giving answer 5100 must learn Simple Interest chp from rs Aggarwal first and then come here..... sum is 850
• 9 years agoHelpfull: Yes(0) No(0)
• p + (p*r*t)/100 = 1020
  =>p + (p*5*4)/100 = 1020
  =>p + p/5 = 1020
  =>6*p/5 = 1020
  =>p = 850
• 8 years agoHelpfull: Yes(0) No(0)
• x+(20x/100)=1020
  x=1020*5/6
  x=850
• 8 years agoHelpfull: Yes(0) No(0)