if m+n is diveded by 12 then remainder is 8 and m-n diveded by 12 them remainder is 6 mn is diveded by 6 then remainder is?

• if m+n is divided by 12 then remainder is 8
  so m+n = 12x+8
  and m-n divided by 12, remainder is 6
  so
  m-n= 12y+6
  
  From these 2 equations, we get
  m= 6(x+y)+7
  n= 12(x+y)+1
  put x+y=k, then
  mn = (6k+7)*(6k+1) = 36 k^2+48k+6+1
  or
  6(6k^2+8k+1)+1
  
  when mn is divided by 6, remainder will be 1 as first terms in expression of mn are multiple of 6...:)
• 12 years agoHelpfull: Yes(6) No(1)
• if m+n is divided by 12 then remainder is 8
  so m+n = 12x+8
  and m-n divided by 12, remainder is 6
  so
  m-n= 12y+6
  
  From these 2 equations, we get
  m= 6(x+y)+7
  n= 12(x+y)+1
  put x+y=k, then
  mn = (6k+7)*(6k+1) = 36 k^2+48k+7
  
  when mn is divided by 12, remainder will be 7 as first two terms in expression of mn are multiple of 12.
  
  so remainder is 7.
• 12 years agoHelpfull: Yes(2) No(8)
• (m+n)2-(m-n)2=4mn
  (8)2-(6)2=4mn
  24=4mn
  mn=7
  but we divide mn by 6 then mn becomes double
  remainder is 7*2=14
• 12 years agoHelpfull: Yes(0) No(0)