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radius of sphere is increased by 10%.what is the % increased by surface area?
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- ans is 21%.
take radius 100. then surface area will be 4*22/7*100*100.
after increase radius by 10% the radius become 100+10% of 100=110,then new surface area will be 4*22/7*110*110.
then increase in surface area percentage ((4*22/7)*110*110 -(4*22/7)*100*100)/(4*22/7-100*100)=0.21*100=21%. - 12 years agoHelpfull: Yes(11) No(0)
- suppose first sphere= 4*pi*100*100 (1)
after increase in radius = 4*pi*110*110 (2)
according (1)&(2)
ANS=21%
- 12 years agoHelpfull: Yes(2) No(0)
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