exam Maths Puzzle Numerical Ability

A person invested $17,000 for one year, part at 10% part at 12% and the remainder at 15%. The total annual income from these investments was $2110. The amount of money invested at

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Solve for y:
2x-3y=12

This is what I got:
3y=12-2x
y=12-2x over
3
y=2-4x over
3
(2x+5)/(x^2+8x+15)-(x+2)/(x^2+8x+15)