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at the end of 1994 rohit was 1/4th as his grany.the sum of the years in which they wer born is 3843.how old was rohit at the and of 2001? explain
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- r=g/4, 1994-r+1994-g=3843, by solving we get r=29, in 1994 rohit age was 29. therefore his age on 2001 is 36.
- 12 years agoHelpfull: Yes(22) No(0)
- grenny = P yrs rohit = P/4 yrs
after 7yrs
grenny = P+7 rohit = (P/4)+7
let birth yr of grenny = a
and that of rohit = b
so a+b = 3843
a = 2001-(P+7)
and b = 2001-(P/4+7)
so 2001-(P+4)+2001-(P/4+7)=3843
frm here p=116yrs
so rohit's age in 2001 = 116/4+7 = 36 - 12 years agoHelpfull: Yes(13) No(0)
- frm the question r-g/4=1994
(1994-r)+(1994-g)=3843
(1994-g/4)+(1999-g)=3843 =>since r=1/4 grani age:r=g/4
-g/4-g=3843-3988
-g-4g/4=-145
g=116
since r=g/4
r=116/4=29 =>in 1994 for 2001 add 7 to dis age
r=29+7=36ans
- 12 years agoHelpfull: Yes(4) No(0)
- rohit age in 2001 is 36.
- 12 years agoHelpfull: Yes(0) No(3)
- rohit will be 34 years at the end of 2001
- 12 years agoHelpfull: Yes(0) No(6)
- In 1994 rohit age=grany's age/4
let rohit born in y1 and grany born in y2
y1+y2=3843
rohit age in 1994=1994-y1=grany/4
grany age in 1994=1994-y2=grany
divide these eq u get 4y1-y2=5982
solve y1=1965
then in 2001 rohit age is 36
divide these
- 12 years agoHelpfull: Yes(0) No(0)
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