find the value of n?where 3^48+3^1996+3^3943+3^3n.....ans is 1963..i want the explanatio.

• see subtracting powers of each coefficient 1996-48 = 1948
  3943-1996= 1947
  similary 3n-3943=1946
  
  solving for n , n comes out to be 1963.
• 12 years agoHelpfull: Yes(38) No(1)
• i think
  1996-48= 1948;
  3943-1996= 1947;
  so next term should be 3943+1946= 5889...
  as 3n= 5889
  so n= 1963... ans..
• 12 years agoHelpfull: Yes(9) No(1)
• using formula (a+b)^3, it is the expansion of this formula
  we can write it as
  (3^16)^3+ (3^n)^3+3*3^32*3^n+3*3^16*3^2n
  now compare the power of third term with 3^1996
  33+n=1996
  n=1963
• 12 years agoHelpfull: Yes(9) No(1)
• check the option.no.should be divisible by 3.i think given ans. is wrong.
• 12 years agoHelpfull: Yes(0) No(11)
• substract the powers..i.e 1996-48=1948,3943-1996=1947(diff. is 1) .
  next diff. 3943+1946=5889.
  so.... 5889/3=1963(ans)
• 7 years agoHelpfull: Yes(0) No(0)