. If each side of a rectangle is increased by 100%, by wat % the area increases?

• if length is l and width is b then area=l*b
  now new l and b is 2l and 2b respectively.
  so new area is=4*l*b
  % increase= 300%
• 12 years agoHelpfull: Yes(41) No(10)
• if length is l and width is b then area=l*b
  now new l and b is 2l and 2b respectively.
  so new area is=4*l*b
  % increase= 300%
• 12 years agoHelpfull: Yes(9) No(6)
• let length=l..breadth=b
  original area=l*b
  inc. length=l+l=2l..breadth=b+b=2b
  now inc. in area=2l*2b=2(l*b)=l*b + l*b
  hencethere is 100% inc. in new area
• 12 years agoHelpfull: Yes(8) No(54)
• Let the length of the rectangle = l
  Let the breadth of the rectangle = b
  Then the area of the rectangle(A) = length x Breadth
  = l*b
  According to the question,
  Length = l + 100/100*l
  = l+l
  = 2l
  Breadth = b + 100/100*b
  = b+b
  = 2b
  New Area(A') = length x breadth
  = 2l x 2b
  = 4lb
  = 4A
  Increase in area = 4A-A
  = 3A
  Increase percentage = Increase in amount/Original Amount*100 %
  = 3A/A*100 %
  = 300%
  
  Therefore area is increased by 300%
• 11 years agoHelpfull: Yes(7) No(0)
• anshul plz update some more questions..
  
• 12 years agoHelpfull: Yes(1) No(3)
• four time
  area=l*b;
  length is double then
  (2*l)*(2*b)=area;
  so its 4 time of area.
• 11 years agoHelpfull: Yes(1) No(1)
• area of rectangle is 2(l+b)
  now by 100% increase ie 2 times we get 2(2l+2b)=2(2(l+b))
  hence area increases 2 times ie 100%
• 11 years agoHelpfull: Yes(1) No(7)
• let length be x and breadth be y..so area= xy
  now sides increased by 100%...
  new length=x+100/100(x)
  =2x
  new breadth=y+100/100(y)
  =2y
  so new area =4xy
  now % increase in area =[(4xy-xy)/xy]*100
  =300%
• 11 years agoHelpfull: Yes(1) No(0)