Elitmus
Exam
Numerical Ability
Permutation and Combination
In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?
Options
1) 1
2) 126
3) 63
4) 64
Read Solution (Total 7)
-
- 7C5*3C2=63
- 9 years agoHelpfull: Yes(7) No(0)
- 7c5*3c2=(7!/5!*2!)*(3!/2!*1!)=63
- 9 years agoHelpfull: Yes(1) No(0)
- 126 7c5*3c2=126
- 9 years agoHelpfull: Yes(1) No(3)
- 63
7C5 * 3c2 = 63 - 9 years agoHelpfull: Yes(1) No(0)
- Ans :3)63
select 5 men from seven and select 2 women from 3
7C5*3C2=63 - 9 years agoHelpfull: Yes(0) No(0)
- (7C5 x 3C2) = 63.
- 9 years agoHelpfull: Yes(0) No(0)
- Answer is 63 .
7C5*3C2 = '63' - 2 years agoHelpfull: Yes(0) No(0)
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