on a particular date both boys and girls appeared for an exam . if 1/4 of the boys and 3/8 of the girls qualified.what is the fractional part of total no. of candidates who qualified?

• (1/4)+(3/8)=.625
  .625/2=5/16
  cz here let biys=1 girls=1 so total =2
• 11 years agoHelpfull: Yes(4) No(4)
• fraction of boys qualified= 1/4
  fraction of girls qualified = 3/8
  hence,fractional part of total no. of candidates who qualified=
  (1/4*3/8)/{(1/4*3/8)+(3/4*5/8)} =1/6(ans)
  
  {where 3/4= no. of not qualified boys, 5/8= no. of non qualified girls){using concept of probability}
  
• 11 years agoHelpfull: Yes(3) No(2)
• if we take equal no of boys and girls are equal then ans is 5/16
  but if boys and girls are not equal then cannot be determined
  
• 11 years agoHelpfull: Yes(1) No(1)