mixture of milk and water has been kept in two separate containers.ratio of milk to water in one of the containers is 5:1 and that in the other container is 7:2. in what ratio the mixtures of these two containers should be added together so that the quantity of the milk in the new mixture may becomes 80%?

• Let the CP of milk be 1Rs
  milk in 1 lt of mixture of container A=5/6
  " " " " " " " " " " " " " " " " " B=7/9
  " " " " " " " " " " " " " " " " " " C=8/10
  Required Ratio=>(8/10)-(7/9):(5/6)-(8/10)
  =>6:9
• 11 years agoHelpfull: Yes(14) No(5)
• simple allegation problem
  find the fraction of milk in all 3 mixtures:
  V1----5/6
  V2----7/9
  Resultant---4/5
  
  5/6 7/9
  
  4/5
  --->(4/5 -5/6):(7/9-4/5)
  --->(1/45 : 1/30)
  --->2:3(ans)
• 11 years agoHelpfull: Yes(12) No(1)
• both of the mixtures should be mixed in ratio 2:3
  
• 11 years agoHelpfull: Yes(5) No(3)
• ratio of both the mixtures should be 2:3
• 11 years agoHelpfull: Yes(3) No(2)
• 2:3 by alligation
  
• 11 years agoHelpfull: Yes(1) No(2)
• ratio of milk in first condition=5/6
  ratio of milk in 2nd condition=7/9
  
  ratio of milk required=80%=4/5
  let x amount is taken form 1st container and y amount form 2nd.
  so, 5x/6+7y/9=4
  and x+y=5
  solving we get,x=2,y=3
  ratio=2/3
• 5 years agoHelpfull: Yes(1) No(0)
• Lcm of 5+1=6 and 7+2=9 is 18 .So 15+21=36,3+6=6 Ans 4:1
• 5 years agoHelpfull: Yes(0) No(2)
• A->M:W=5:1=5/6 , B->M:W=7:2=7/9 and C->8/10
  Required ratio= (8/10)-(7/9):(5/6)-(8/10)
  =6:9
• 4 years agoHelpfull: Yes(0) No(0)