7 equidistant horizontal lines intersect 12 euidistant vertcallines to form a gridthe smallest rectangles are squares ...how many squares???

• 12*7+11*6+10*5+9*4+8*3+7*2+6*1=280
• 12 years agoHelpfull: Yes(17) No(2)
• 11*6+10*5+9*4+8*3+7*2+6*1=196
• 12 years agoHelpfull: Yes(13) No(5)
• 7C2*12C2 =1386
• 12 years agoHelpfull: Yes(10) No(3)
• for every 2line there a new rectangle is generated so we will take the combinations....
  7c2*12c2=1386
• 12 years agoHelpfull: Yes(3) No(2)
• (11*7)+ (10*6)+ (9*5) + 8*4 + 7*3 + 6*2 + 7*1 = 260
  
• 12 years agoHelpfull: Yes(1) No(6)
• divyakar awasthi is ryt
• 12 years agoHelpfull: Yes(1) No(2)
• it is 196....u r ri8 bhanu...
• 12 years agoHelpfull: Yes(1) No(3)
• ans is 280...
  
• 12 years agoHelpfull: Yes(1) No(2)
• 280
  size vertical plane horizontal plane no of sqaures
  1X1 12 7 12*7
  2X2 11 6 11*6
  
  likewise,we get
  12*7 + 11*6 + 10*5 + 9*4 + 8*3 + 7*2 + 6*1=280
• 12 years agoHelpfull: Yes(1) No(1)
• thnx buddy @ swarup
• 12 years agoHelpfull: Yes(1) No(0)
• (m*n)+(m-1)*(n-1)+(m-2)*(n-2)+........upto mul become 0;
  
  12*7+11*6+10*5+9*4+8*3+7*2+6*1=280
• 12 years agoHelpfull: Yes(1) No(0)
• [n(n+1)(2n+3t+1)/6] for (n*n+t)
  hence. 196
• 12 years agoHelpfull: Yes(0) No(2)