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If a^x= b , b^y= c and c^z = a ,, then what is the value of x*y*z ?
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- ((((a)^x)^y)^z)=a
so.(a)^xyz=a
so xyz=1 - 12 years agoHelpfull: Yes(6) No(0)
- here b=c^zx
b^y=c^zxy
c=c^zxy
hence 1=z*x*y - 12 years agoHelpfull: Yes(2) No(0)
- its x=log(b,a); y=log(c,b),
;z=log(a,c) so xyz=log(b,a)*log(c,b)*log(a,c)=log(a,a)=1. after cancelling the chain - 12 years agoHelpfull: Yes(1) No(0)
- a^x=b can be written as log b base a =x-(1)
Similarly y= log c base b-(2)
Z= log a base c-(3)
If we multiply 1,2,3
We will get log 1 =0
So ans is 0 - 7 years agoHelpfull: Yes(0) No(0)
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