a product of ages of ankit and nikita is 240. if twice the age of nikita is more than ankit's by 4 years. what is the nikita's age?

• if ankit age=x
  nikita age=240/x
  then (2*(240/x))-x=4 so,x=20
  ankit age=20yrs
  nikita age=(240/20)=12yrs
• 12 years agoHelpfull: Yes(25) No(3)
• Ankita=x, nikita=y;
  two equations are xy=240
  2y=x+4
  x=20,y=12
  ans is 12
  
• 12 years agoHelpfull: Yes(11) No(1)
• let the age of nikita is x
  xy=240
  2x-y=4
  2x-240/x=4
  x=12(ans)
• 12 years agoHelpfull: Yes(6) No(2)
• if ankit age=x
  nikita age=240/x
  then (2*(240/x))-x=4 so,x=20
  ankit age=20yrs
  nikita age=(240/20)=12yrs
• 12 years agoHelpfull: Yes(5) No(2)
• 12
  xy=240
  2x-y=4
  solving these x=12
  
• 12 years agoHelpfull: Yes(2) No(1)
• let ankit's age be X years then Nikita age=240/X years
  Therefore 2*(240/X)-4 480-X^2=4X x^2+4X-480=0
  (X+24)(X-20)=0 X=20
  Hence Nikita's age= (240/20)years=12years
• 11 years agoHelpfull: Yes(2) No(0)
• ankit's age=20 yrs
  nikita's age=12 yrs
  let ankit's age be a yrs
  and nikita's age will be n yrs
  so the reqd eqn is
  a^2+4a-480=0
• 11 years agoHelpfull: Yes(2) No(0)
• nikita age is 12...na=240...and 2n=a+4....solving these we get n=12...
• 12 years agoHelpfull: Yes(1) No(0)
• a*n = 240
  2n-4 = a
  n^2-2n-120=0
  n=12
  nikita = n
  ankit = a
  age of nikita = 12 yrs
• 11 years agoHelpfull: Yes(1) No(0)
• a.n=240
  and 2n-a=4
  so a=2n-4
  put it in 1st eqn n=12 so a=20
• 11 years agoHelpfull: Yes(1) No(0)
• ans is 12
• 11 years agoHelpfull: Yes(1) No(1)